Alright! Here's an idea for a game that noone will play!
First person posts an integral to calculate. Can de definite or indefinite, your choice.
The next person posts their calculations - not just the answer, the best thing would be a photo of the sheet of paper you wrote on. Just to prove that you actually calculated things, you know.
Then check your answer on Wolfram Alpha. Then post another integral for the next person to calculate!
Sounds easy enough, right?!
(I'm gonna be bumping this a few times probably XD)
Here's the first one:
∫(x3+x)e5xdx
Oh and you can offer prizes too, and maybe I'll do that later (probably not).
Alright! Here's an idea for a game that noone will play!
First person posts an integral to calculate. Can de definite or indefinite, your choice.
The next person posts their calculations - not just the answer, the best thing would be a photo of the sheet of paper you wrote on. Just to prove that you actually calculated things, you know.
Then check your answer on Wolfram Alpha. Then post another integral for the next person to calculate!
Sounds easy enough, right?!
(I'm gonna be bumping this a few times probably XD)
Here's the first one:
∫(x3+x)e5xdx
Oh and you can offer prizes too, and maybe I'll do that later (probably not).
how to not sad
For the math nerds and next semester, me! @
Origamer
For the math nerds and next semester, me! @
Origamer
Hey if noone plays that's fine, I'll solve it myself and post another one XD
Hey if noone plays that's fine, I'll solve it myself and post another one XD
how to not sad
@SGF
not sure how well my camera works, or how well i know how to use computers but:
[img]http://orig09.deviantart.net/0d8e/f/2016/256/9/b/snapshot__6__by_catsez-dahj3j2.jpg[/img]
[img]http://orig09.deviantart.net/572b/f/2016/256/a/e/snapshot__5__by_catsez-dahj3u3.jpg[/img]
the first time i tried to do it the "31"s were "19"s so ¯\_(?)_/¯
[b]∫(1+cos(x))/(x+sin(x))dx[/b]
@
SGF
not sure how well my camera works, or how well i know how to use computers but:
the first time i tried to do it the "31"s were "19"s so ¯\_(?)_/¯
∫(1+cos(x))/(x+sin(x))dx
I'll just give it a bump since this thing deserves it.
I'll just give it a bump since this thing deserves it.
Darn. I need to do some more calculus.
Trying to take precalculus (well, finish it), trigonometry, and calculus at the same time makes things difficult. :P If I'd gotten to this point I would be digging this game.
^This is also another bump, because yes, it does deserve it.
Darn. I need to do some more calculus.
Trying to take precalculus (well, finish it), trigonometry, and calculus at the same time makes things difficult. :P If I'd gotten to this point I would be digging this game.
^This is also another bump, because yes, it does deserve it.
This game deserves a bump for its uniqueness and interesting use of the forum boards. I'd try to play but I am nowhere near your level of calculation. I'll stick to literary-based games.
This game deserves a bump for its uniqueness and interesting use of the forum boards. I'd try to play but I am nowhere near your level of calculation. I'll stick to literary-based games.
Hehe maybe I'll give this a shot when I didn't just wake up! Calc is pretty cool.
@
SGF
Love the XKCD signature. ;)
Hehe maybe I'll give this a shot when I didn't just wake up! Calc is pretty cool.
@
SGF
Love the XKCD signature. ;)
@Tos97, showing my false start for the lulz.
∫(1+cos(x))/(x+sin(x))dx
= ∫dx/(x + sinx)+∫cos(x)/(x+sinx)dx
Five (!!) years ago, I could've done this without u-sub, but I'm a newb again, now, so:
u = x + sinx
du = (1 + cosx) dx
...wait a second.
∫(1+cos(x))/(x+sin(x))dx
= ∫du/u
= ln|u| + C [honestly don't remember if it's ln(u) or ln|u| doesitevenmatter*]
= ln|x + sin(x)| + C
*Yes, it matters because I'd hate to take the log of a negative. Or zero.
My turn! [rubs hands and cackles]
[quote=I]
∫e^(2x)cos(2x)dx
[/quote]
@
Tos97, showing my false start for the lulz.
∫(1+cos(x))/(x+sin(x))dx
= ∫dx/(x + sinx)+∫cos(x)/(x+sinx)dx
Five (!!) years ago, I could've done this without u-sub, but I'm a newb again, now, so:
u = x + sinx
du = (1 + cosx) dx
...wait a second.
∫(1+cos(x))/(x+sin(x))dx
= ∫du/u
= ln|u| + C [honestly don't remember if it's ln(u) or ln|u| doesitevenmatter*]
= ln|x + sin(x)| + C
*Yes, it matters because I'd hate to take the log of a negative. Or zero.
My turn! [rubs hands and cackles]
I wrote:
∫e^(2x)cos(2x)dx
|
When people draw up a warm bath and put in flower petals,
|
Blue // they/he 
